SSC JE Mechanical Engineering 2013 Paper

Question : 121 of 200

Marks: +1, -0

Tension in the tight side of a belt drive is 100 N and that in the slack side 60 N. If the belt breadth is 10 cm and thickness 4 cm, what is the maximum stress induced in the belt?

2.5 N/cm $^{2}$
1.5 N/cm $^{2}$
4 N/cm $^{2}$
2 N/cm $^{2}$

Validate

Solution:

Maximum stress will be on tight side of belt.
∴

σ_\max. ={T (\tigh \side) }/{\Cross-\section \area \of \belt}

{160N}/{40×10\cm^2}=2.5\ \N\/\cm^2

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