SSC JE Mechanical Engineering 2013 Paper

Question : 104 of 200

Marks: +1, -0

The maximum and minimum speeds of a flywheel during a cycle are

N_1

and

N_2

r.p.m. respectively.
The coefficient of steadiness of the flywheel is

Solution:

For fly wheel coefficient of steadiness coefficient of steadiness

=1/{\Coeff. \of \fluctuation \of \speed}

N_\mean/{N_\max -N_\min}={(N_1+N_2)/2}/ {({ N _1-N_2 } ) }

={ N_1+ N _2}/{2(N _1-N_2 )}

Go to Question:

Prev Question

Next Question