SSC JE Mechanical Engineering 2012 Paper

Question : 164 of 200

Marks: +1, -0

The inner and outer radius of friction surface of a plate clutch are 50 mm and 100 mm respectively.
What is the ratio of maximum intensity of pressure to minimum intensity of pressure on clutch plate if magnitude of axial force is 4 kN?
Assume uniform wear theory.

Validate

Solution:

r_i = 50

r_0 = 100

mm
w = 4 KN
Using uniform wear theory

{{P_\max=w/{2πr_i(r_0-r_l)}}/{{P_\min}=w/{2πr_0(r_0-r_i)}}=r_0/r_i

=100/50=2

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