SSC JE Mechanical Engineering 2012 Paper

Question : 134 of 200

Marks: +1, -0

Pressure of 80 kPa is equivalent to head in metre of carbon tetrachloride of relative density 1.59 of the value

Solution:

Pressure P = ρgh

80 × 10^{3} = (1000× 1.59) ×9.81× h

[h =5.13\m]

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