SSC JE Mechanical Engineering 2012 Paper

Question : 103 of 200

Marks: +1, -0

In case of Boyle’s law, if pressure increases by 1%, the percentage decrease in volume is

Solution:

From the Boyel's low
PV = C

P _1V _1=P_2 V_2

∵

P_2=1.01 P_ 1

P_1 V_1=1.01 P_1× V_2

V_2=V_1/1.01={100V_1}/101

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