SSC JE Mechanical Engineering 11 Oct 2020 Shift 1 Papers

The logic followed here is:-
The code is the positional values of each alphabet.
For SUHANI:-
$\begin{array}{cccccc}\mathit{S}& \mathit{U}& \mathit{H}& \mathit{A}& \mathit{N}& \mathit{I}\\ \downarrow & \downarrow & \downarrow & \downarrow & \downarrow & \downarrow \\ 19& 21& 8& 1& 14& 9\end{array}$
Similarly, for TUSHAR:-
$\begin{array}{cccccc}\mathit{T}& \mathit{U}& \mathit{S}& \mathit{H}& \mathit{A}& \mathit{R}\\ \downarrow & \downarrow & \downarrow & \downarrow & \downarrow & \downarrow \\ 20& 21& 19& 8& 1& 18\end{array}$
Hence, the correct answer is "2021198118".