SSC JE Mechanical Engineering 11 Oct 2020 Shift 1 Papers

Question : 185 of 200

Marks: +1, -0

The absolute pressure at a depth of 500 cm below the surface of a fluid of relative density 0.85 is equal to:

Solution:

Given:
h = 500 cm = 5 m

P_g = ρ × g × h = 0.85 × 1000 × 9.8 × 5

= 41650 N\/m^2

= 0.041650 N\/mm^2 = 0.041650 MPa

∴ using equation (i)

P = 0.101325 + 0.041650

P = 0.142975 ≈ 0.141

MPa

Go to Question:

Prev Question

Next Question