SSC JE Mechanical Engineering 11 Oct 2020 Shift 1 Papers

Question : 140 of 200

Marks: +1, -0

The water is flowing through a pipe having areas 0.05

m^2

and 0.01

m^2

at sections 1 and 2 respectively. The rate of flow through the pipe is 50 litres per second in section 1. The velocity at sections 1 and 2 are:

Solution:

Given:
Area:

{A}_{1}=0.05 {m}^{2}, {A}_{2}=0.01 {m}^{2}

Flow rate:

Q=50\;1\/ {s}=50 \×10^{-3} {m}^{3} \/ {s}

{Q}={A}_{1} {V}_{1}={A}_{2} {V}_{2}

{V}_{1}={{Q}}/{{A}_{1}}={50 \×10^{-3}}/{0.05}=1

m/s

{V}_{2}={{Q}}/{{A}_{2}}={50 \×10^{-3}}/{0.01}=5

m/s.

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