SSC JE Mechanical Engineering 11 Oct 2020 Shift 1 Papers

Question : 138 of 200

Marks: +1, -0

Brake thermal efficiency of a 15 kW IC engine is 30%. If the fuel used has CV 40 MJ/kg, then the fuel consumption rate in kg/h is:

Solution:

\η _{\text "bth "}=0.3, {CV}=40 \×10^{3} {kJ} \/ {kg}, {BP}=15 {kJ} \/ {s}

Now,

\∴0.3={15}/{40 \×10^{3} \×{m}_{f}}

{m}_{{f}}={15}/{0.3} \×{1}/{40000} \×3600 {{kg}}/{{hr}}

∴ m_f = 4.5

kg/hr

Go to Question:

Prev Question

Next Question