SSC JE Mechanical Engineering 11 Oct 2020 Shift 1 Papers

Density of mercury, ρ = 13.658 g/cc = 13.58 × 10${}^3$ kg/m${}^3$ , Pressure = 4 kPa
Now pressure in terms of mercury column
∵ P = ρ × g × h
$4\times {10}^3=13.58\times {10}^3\times 9.81\times \mathit{h}$
h = 0.03004 m
Hence, h = 30.04 mm of Hg