SSC JE Mechanical Engineering 11 Oct 2020 Shift 1 Papers

Question : 121 of 200

Marks: +1, -0

The reaction and bending moments at point A of the cantilever beam are:

Solution:

Given:

{R}_{{Av}}=

Vertical reaction at

{A}, {R}_{{Ah}}=

Horizontal reaction at

{A}, {M}_{{A}}=

Moment at

{A}

\∑{F}_{{V}}=0

{R}_{{Av}}-10-5-15=0

{R}_{{Av}}-30=0 \⇒{R}_{{Av}}=30 {kN}

\∑{M}_{{A}}=0 \

⇒{M}_{{A}}+(10 \×1)+(5 \×3)+(15 \×6)=0

{M}_{{A}}+115=0 \⇒{M}_{{A}}=-115 {kNm}

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