SSC JE Electrical Engineering 26 Sep 2019 Shift 2 Paper

Question : 169 of 200

Marks: +1, -0

Observe the given figure. Find Thevenin's resistance as seen from open circuited terminals.

Solution:

Deactivating all the sources we get

{20×80}/{20+80}=1600/100=16Ω.

∴

R_{\TH }= 16 × 2

= 32Ω

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