SSC JE Electrical Engineering 26 Sep 2019 Shift 2 Paper

If a circular conductor carries a current ‘I’ ampere having radius ‘r’ metre, then magnetizing force at the centre of the coil is given by
$\frac{\mathit{I}}{2\mathit{r}}$At / m
Potential at point a
$\frac{{\mathit{V}}_{\mathit{a}}-{\mathit{E}}_1}{{\mathit{R}}_1}=-{\mathit{I}}_1$
∴ $]{\mathit{V}}_{\mathit{a}}={\mathit{E}}_1-{\mathit{I}}_1{\mathit{R}}_1]$ and $\frac{{\mathit{V}}_{\mathit{a}}-0}{{\mathit{R}}_3}={\mathit{I}}_3$
∴ $\left[{\mathit{V}}_{\mathit{a}}={\mathit{I}}_3{\mathit{R}}_3\right]$