SSC JE Electrical Engineering 26 Sep 2019 Shift 2 Paper

Question : 144 of 200

Marks: +1, -0

If the connected light load in a house is 3000W and power sub-circuit load 6000W, then what is the number of sub-circuits required?

Solution:

No. of sub circuit required =

{\Power \sub \circuit}/{\Light \load}

= 6000/3000=2

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