SSC JE Electrical Engineering 26 Sep 2019 Shift 2 Paper

Question : 12 of 200

Marks: +1, -0

Three persons A, B and C have different amount of rupees with them. If A gives 11 rupees to B, A will have equal amount as C has. A and C together have total 161 rupees. B has 7 rupees less than C. How many rupees does B have?

Validate

Solution:

A – 11 = C ...(1)
A + C = 161 ...(2)
C – B = 7 ...(3)
Solving equation (1) and (2) we get

A - C= 11

A+ C =161

- - - - - - - - - -

2A =172

[A=86]

∴

[C=75]

⇒

B = C – 7

75 – 7

= 68

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