SSC JE Electrical Engineering 26 Sep 2019 Shift 1 Paper

Question : 180 of 200

Marks: +1, -0

A coil is wound with 50 turns and a current 8A produces a flux of 200µWb. Calculate the inductance of the coil.

Solution:

Given data,
N = 50
I = 8A
ϕ = 200 µwb
L = ?
Now,

L = {Nϕ}/ I

{50× 200 ×10^{-6}}/8

1250 × 10^{–6}

∴

L = 1.25 mH

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