SSC JE Electrical Engineering 26 Sep 2019 Shift 1 Paper

Question : 175 of 200

Marks: +1, -0

In the circuit shown, find the equivalent resistance between A and B.

Solution:

Redrawing above circuit,

∴

R_{\eq} = 10000/ 400

∴

R_{\eq| = 25

R_{\AB} = (50 + 25)Ω= 75Ω

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