SSC JE Electrical Engineering 26 Sep 2019 Shift 1 Paper

Question : 157 of 200

Marks: +1, -0

The voltmeter shown in the circuit reads:

Solution:

D=V/I

I=(24/{500MΩ})A

Now V = IR
=

(24/{500MΩ}×250MΩ)

=24/2

∴ V = 12V

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