SSC JE Electrical Engineering 26 Sep 2019 Shift 1 Paper

Question : 144 of 200

Marks: +1, -0

In an AC network, the load connected is (10 +j10).
The phase relation between the voltage applied and the current through the load is:

Solution:

Z = 10 + j10
∴

\tan θ=10/10

∴

\tan θ= 1

∴

θ = 45°

∴ Voltage leads current by 45°

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