SSC JE Electrical Engineering 24 Jan 2018 Morning Paper

Question : 191 of 199

Marks: +1, -0

The maximum efficiency of a half wave rectifier is

Solution:

In half wave rectifier

\η=0.406/{1+R_F/R_L}

For maximum effciency neglect

R_F

compared to

R_L

\η_\max=40.6%

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