SSC JE Electrical Engineering 24 Jan 2018 Morning Paper

Question : 130 of 199

Marks: +1, -0

What will be value of magnetic field (in mT) at the centre of a 8 m long coil, when the coil has 260 turns and carrying a current of 4 A?

Solution:

l = 8 m
N = 260
I = 4 A
B = ?
Magnetic field inside coil is given by B

={\µ_0\NI}/\l

∴B={4π×10^{-7}×260×4}/8

= 0.163 mT

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