SSC JE Electrical Engineering 24 Jan 2018 Evening Paper

Question : 135 of 200

Marks: +1, -0

Calculate the value of phase angle (in Degrees) in a series RC circuit having a resistance of 50 Ohms and a capacitive reactance of 86.6 Ohms, when supplied with a frequency of 50 Hz.

Validate

Solution:

cos

ϕ=R/√{R^2+{X^2}_C

where ‘ϕ’ is phase angle in a series RC circuit.
cos

ϕ=50/√{50^2+(86.6)^2

50/1000=1/2

ϕ = 60°

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