SSC JE Electrical Engineering 24 Jan 2018 Evening Paper

Question : 131 of 200

Marks: +1, -0

What will be the instantaneous value of the alternating current (in A) which is represented by i(t) = 20 sin (13t – 20) A, when the value of t is 5?

Solution:

i(t) = 20 sin (13t – 20)A
at t = 5 sec
i(t) = 20 sin (65 – 20)A
= 20 sin 45

=20/√2

= 14.4 A

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