SSC JE Electrical Engineering 24 Jan 2018 Evening Paper

Question : 106 of 200

Marks: +1, -0

What is the equivalent capacitance (in µF) for the circuit given below?

Solution:

C=((C_1||C_2+C_3)||(C_4||C_5))

=((10||30+20)||(10||10))

=(7.5+20)||5=27.5||5

= 4.32 µF

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