SSC JE Electrical Engineering 24 Jan 2018 Evening Paper

Question : 104 of 200

Marks: +1, -0

What is the resistivity (in Ohms-m) of a 2 Ohm cylindrical wire when the length and the diameter of the wire are 10 m and 0.4 m respectively?

Solution:

ρ = Resistivity of conductor Material
l = length of conductor
A = Cross– section Area of conduction

R=\ρ\l/A⇒\ρ={RA}/\l

⇒\ρ=2×π/4×(0.4)^2/10

= .025

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