SSC JE Electrical Engineering 24 Jan 2018 Evening Paper

Question : 102 of 200

Marks: +1, -0

How much power (in W) will be dissipated by a 5 Ohm resistor in which the value of current is 2 A?

Solution:

Power dissipated (P)

= I^ 2 R

= (2)^2 × 5

= 20 Watt

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