SSC JE Electrical Engineering 23 Jan 2018 Morning Paper

Question : 134 of 200

Marks: +1, -0

In a parallel resonant circuit, the input impedance of the circuit is__________.

Solution:

For parallel RLC circuit

Y=G+j(ωC-1/{ωL})

At resonance

ωC=1/{ωL}

∴ |Y| = G (minimum)

Z =1/Y

= maximum

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