SSC JE Electrical Engineering 23 Jan 2018 Morning Paper

Question : 125 of 200

Marks: +1, -0

What will be the permeance (in H) of a coil, when the flux through the coil is 50 Wb and the value of produced mmf is 25 Amp–turns?

Solution:

Given data
Flux = 50 wb
and - mmf = 25 A-T
Now permeance

=1/\Reluctance

and reluctance

=\mmf/\flux

⇒ Permeance

=\flux/\mmf=50/25=2H

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