SSC JE Electrical Engineering 23 Jan 2018 Evening Paper

Question : 150 of 200

Marks: +1, -0

Determine the flux (in Wb) through a coil when the reluctance of the coil is 4 Amp-turns/Wb and the produced mmf is 48 Amp-turns.

Solution:

Maximum Torque in 3-phase induction motor
Flux (ϕ)

=\MMf/\Reluctance

=48/4=12

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