SSC JE Electrical Engineering 23 Jan 2018 Evening Paper

Question : 131 of 200

Marks: +1, -0

A resistance of 75 Ohms is connected in shunt of a galvanometer, having an internal resistance of 25 Ohms, to convert it into an ammeter. What is the value of current (in A) flowing through the galvanometer, if the total current in the circuit is 5 A?

2
2.5
3.65
3.75

Validate

Solution:

\I_m=\R_\sh/{R_m+\R_\sh}

={5×75}/(25+75)

= 3.75 A

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