SSC JE Electrical Engineering 23 Jan 2018 Evening Paper

Question : 105 of 200

Marks: +1, -0

Determine the energy (in J) stored by a 0.4 H inductance, if the current flowing through it is 2 A.

Solution:

Energy store in inductor

(w)=1/2LI^2

=1/2×0.4×2^2

= .8 joule

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