SSC JE Electrical Engineering 22 Jan 2018 Evening Paper

Question : 129 of 200

Marks: +1, -0

Determine the magnetic susceptibility of a material, if the field strength of the material is 0.8 × 10

^{5}

A.m

^{–1}

and the magnitude of magnetization is 0.97 ×10

^{5 }

A.m

^{–1}

Solution:

Given
field Strength (H) = 0.8 × 10

{^5}

^{–1}

and Magnetization (M) = 0.97 × 10

^5

A.m

^{–1}

Now magnetic susceptibility is given by

\X_\m=M/H={0.97×10 ^5}/{0.8×10^5}

= 1.21

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