SSC JE Electrical Engineering 2017 Set 4 Paper

Question : 118 of 200

Marks: +1, -0

The resistance across terminals 'a' and 'b' in the circuit shown will be____

Solution:

For finding resistance across A and B all intern voltage source should short circuit and current source open circuit.

R_1={1.2×4.8}/{4.8×1.2}=5.76/6=96Ω

R_2 = .96

1.2 = 2.16 Ω.

R_\eq={2.16× 3.6}/{2.16× 3.6}

= {2.16× 3.6}/5.76=1.35Ω

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