SSC JE Electrical Engineering 2017 Set 3 Paper

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Question : 147 of 200

Marks: +1, -0

In the network shown in the given figure, if the voltage V at the time considered is 20V, then dV/dt at that time will be :

1V /s
2V/ s
–2V /s
zero

Solution:

At node A,

{20-40}/10+{20-0}/20+i_2=0

-2 + 1 = -i_2

∴

i_2 = 1 A

Now

i_2=C{dv}/{dt}

∴

1=1/2{dv}/{dt}

∴

{dv}/{dt}=2

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