SSC JE Electrical Engineering 2017 Set 2 Paper

Question : 161 of 200

Marks: +1, -0

The voltage regulation of a transformer having copper loss 1% of output and percentage reactance drop of 5% and power factor 0.9 lagging is____:

Solution:

\cos ϕ_2 = .9, \sin ϕ_2 = .53

Voltage regulation at .9PF lagging

= \Re_2 \cosϕ_2 + \Xe_2 \sin ϕ_2

= 1 × .9 + 5 × .53

= .9 + 2.179 = 3.07%

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