SSC JE Electrical Engineering 2017 Set 1 Paper

Question : 167 of 200

Marks: +1, -0

Two heaters rated at 1000W, 250 each are connected in series across a 250V, 50Hz ac mains. The total power drawn from the supply would be_____watt.

Solution:

R=V^2 /P

R={250 ×250}/1000=62.5Ω

Total current flow in circuit

=250/{62.5+ 62.5}=2A

Total power drawn from the supply ‘P’
= VI
= 250 × 2 = 500 W

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