SSC JE Electrical Engineering 2017 Set 1 Paper

Question : 119 of 200

Marks: +1, -0

In an R–C–L series circuit, during resonance, the impedance will be

Solution:

during resonance

X_C = X_L

Z=√{ R^2+ (X_C- X_L ) ^2}

Z = R

Then at (series) resonance the independence is minimum.

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