SSC JE Electrical Engineering 2015 Paper

Question : 190 of 199

Marks: +1, -0

A circuit breaker is rated as follows: 1500 A, 33 KV, 3 sec, 3-phase oil circuit breaker.
Determine the making current?

Solution:

Making current = 2.55 × B ... current

I_B=δ /√{3V_L}={2000× 10^6}/{ √3×33×10^3}

= 35kA
Making current = 2.55 × 35 kA = 89 kA

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