SSC JE Electrical Engineering 2014 Set 1 Paper

Question : 158 of 200

Marks: +1, -0

The emf induced in a DC shunt generator is 230 V.
The armature resistance is 0.1 Ω. If the armature current is 200 A, the terminal voltage will be

Solution:

Terminal Voltage of DC shunt generator is
V = E – IaPa
where E is generated EMFI
Ia is armature current
Ra is Armature Resistance
V = 230 – 0.1 × 200

= 230 – 20 = 210 V

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