SSC JE Electrical Engineering 2014 Set 1 Paper

Question : 126 of 200

Marks: +1, -0

A circuit has inductance of 2 H. If the circuit current changes at the rate of 10 A/sec, then selfinduced emf is

Solution:

Self induced EMF (E)

={ Ldi}/d

= 2 × 10 = 20V

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