SSC JE Electrical Engineering 2014 Set 1 Paper

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Question : 120 of 200

Marks: +1, -0

The circuit shown in the given figure is equivalent to a load of

4/3 Ω
8/3 Ω
4 Ω
2 Ω

Solution:

from the circuit drawn,

2I + 2 (I -I') = 4I'

and

I'= 1/4 A

then,

2I + 2 (1- {I/4} )= 1

⇒

I = 3/8 A

Req = V / I =8/3 Ω

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