SSC JE Electrical Engineering 2014 Set 1 Paper

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Question : 115 of 200

Marks: +1, -0

For the circuit shown in figure, when V

_ s

= 0, I = 3A. When V

_ s

= 200 V, what will be the value of I ?

– 4A
– 1A
1 A
7 A

Solution:

Current dursion gives,

I_ s× 30/ 50 = I

⇒

I_s=5/3A

when

V_s = 200 V, I _s = 0

then

I_1=5/3A

Net current,

I = I'+ I" = -4 + 3 = -1A

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