SSC JE Electrical Engineering 2013 Paper

Question : 189 of 200

Marks: +1, -0

A 300 kW alternator is driven by a prime mover of speed regulation 4% while the prime mover of another 200 kW alternator has a speed regulation of 3%. When operating in parallel, the total load they can take without any of them being overloaded is

500 kW
567 kW
425 kW
257 kW

Validate

Solution:

Load share by two × machinery are 'x' kw and 'y' kw.

4/300x=3/200y

8x=9y

x = 225 kw (y = 200 kw given)
Total load = 225 + 200 = 425 kw.

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