SSC JE Electrical Engineering 2013 Paper

Question : 187 of 200

Marks: +1, -0

The magnetic field energy in an inductor changes from maximum value to minimum value in 5 m sec when connected to an ac source. The frequency of the source in Hz is

Validate

Solution:

For quarter part of wave pulse energy going down to maximum value to minimum value i.e.

T/4 =5×10^{-3}\sec

T = 20 msec

f=1/T=50Hz

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