SSC JE Electrical Engineering 2013 Paper

Question : 169 of 200

Marks: +1, -0

Two single-phase ac motors A and B operate from a 1000 V supply. A consumes 2 kW at a power factor of 0.8 (lagging) and B consumes 1 kW at a power factor of 0.5 (lagging). The total current drawn from the supply is approximately

4.5 A
2.1A
4.41A
9A

Validate

Solution:

I_1=P/{V\cosθ_1}

={2×10000}/{1000×0.8}=2.5A

I_2=P/{V\cosθ_2}

=1000/{1000×0.5}=2A

I=I_1+I_2=2.5+2

I=4.5A

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