SSC JE Electrical Engineering 2013 Paper

Question : 160 of 200

Marks: +1, -0

An electric heater draws 1000 watts from a 250 V source. The power drawn from a 200 V source is

Solution:

P=V^2/R

P_1/P_2=V_1^2/V_2^2

1000/P=(250/200)^2

P=1000/25×16=640\W

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