SSC JE Electrical Engineering 2013 Paper

Question : 147 of 200

Marks: +1, -0

A voltmeter when connected across a dc supply, reads 124 V. When a series combination of the voltmeter and an unknown resistance X is connected across the supply, the meter reads 4 V. If the resistance of the voltmeter is 50 kΩ, the value of X is

1550 kΩ
1600 kΩ
1.6 kΩ
1.5 MΩ

Validate

Solution:

Current through voltmeter

I_V=V/R=4/5000

=8×10^{-5}\A

DC supply voltage = 120
then the unknown resistance is give as

R=V/2=120/{8×10^{-5}}=15mp

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