SSC JE Electrical Engineering 2013 Paper

Question : 136 of 200

Marks: +1, -0

In a balanced 3-phase circuit, the line current is 12 A. When the power is measured by two wattmeter method, one meter reads 11 kW while the other reads zero. Power factor of the load is

0
0.5
0.866
1.0

Validate

Solution:

I_L = 12A

W_1 = 11 kW

W_2 = 0

\tanϕ={√3(w_1-w_2)}/{w_1-w_2}

ϕ=60°

Power factor = cos 60°

=1/2 =0.5

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