SSC JE Electrical Engineering 2013 Paper

Question : 130 of 200

Marks: +1, -0

A attenuator probe as shown, is connected to an amplifier of input capacitance 0.1 µ F. Value of C that must be connected across 100 K to make the overall gain independent of frequency, is

0.01 µ F
0.1 µ F
1 µ F
10 µ F

Validate

Solution:

For prob independent of frequency
Time constant of amplifier and prob are equal

R_1C_1= R_2C_2

100 × C = 10 × .1 × 10

^{–6}

1 C = .01 µc

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