SSC JE Electrical Engineering 2012 Paper

Question : 190 of 200

Marks: +1, -0

The mutual inductance between two closely coupled coils is 1 H. If the turns of one coil is decreased to half and those of the other is doubled, the new value of the mutual inductance would be

$1/4$ H
1 H
2 H
$1/2$ H

Validate

Solution:

M = 1H

L ∝ N^2

M = K √{L_1 L_ 2}

M_\new= 1 H

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